需要说明,本文的线程池都是java.util.concurrent.ExecutorService线程池,本文将围绕验证,阅读源码俩方面来解析这个问题。
2.1.1 测试代码:
public class ThreadPoolExecutorDeadTest {public static void main(String[] args) throws InterruptedException {ExecutorService executorService = buildThreadPoolExecutor();executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute-exception"));executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute"));Thread.sleep(5000);System.out.println("再次执行任务=======================");executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute"));executorService.execute(() -> exeTask("execute"));}public static ExecutorService buildThreadPoolExecutor() {return new ThreadPoolExecutor(5, 10, 30, TimeUnit.SECONDS,new LinkedBlockingQueue<>(1000), new ThreadFactoryBuilder().setNameFormat("test-%s").build(), new ThreadPoolExecutor.CallerRunsPolicy());}private static void exeTask(String name) {String printStr = "[thread-name:" + Thread.currentThread().getName() + ",执行方式:" + name + "]";if ("execute-exception".equals(name)) {throw new RuntimeException(printStr + ", 我抛异常了");} else {System.out.println(printStr);}}}
2.1.2 执行结果如下:
public class ThreadPoolExecutorDeadTest {public static void main(String[] args) throws InterruptedException {ExecutorService executorService = buildThreadPoolExecutor();executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute-exception"));executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute"));Thread.sleep(5000);System.out.println("再次执行任务=======================");executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute"));executorService.submit(() -> exeTask("execute"));}public static ExecutorService buildThreadPoolExecutor() {return new ThreadPoolExecutor(5, 10, 30, TimeUnit.SECONDS,new LinkedBlockingQueue<>(1000), new ThreadFactoryBuilder().setNameFormat("test-%s").build(), new ThreadPoolExecutor.CallerRunsPolicy());}private static void exeTask(String name) {String printStr = "[thread-name:" + Thread.currentThread().getName() + ",执行方式:" + name + "]";if ("execute-exception".equals(name)) {throw new RuntimeException(printStr + ", 我抛异常了");} else {System.out.println(printStr);}}}
submit 提交到线程池的方式,如果执行中抛出异常,并且没有catch,不会抛出异常,不会创建新的线程。
3.1 java.util.concurrent.AbstractExecutorService#submit(java.lang.Runnable)
3.2 查看execute方法的执行逻辑java.util.concurrent.ThreadPoolExecutor#runWorker
3.3 java.util.concurrent.ThreadPoolExecutor#processWorkerExit
可以发现,如果抛出异常,会移除抛出异常的线程,创建新的线程。
3.4 为什么submit方法,没有创建新的线程,而是继续复用原线程?
还记得,我们在3.1的时候,发现submit也是调用了execute方法,但是在调用之前,包装了一层 RunnableFuture,那一定是在RunnableFuture的实现 FutureTask中有特殊处理了,我们查看源码可以发现。
但是,我们通过java.util.concurrent.FutureTask#get(),就可以获取对应的异常信息。
当一个线程池里面的线程异常后:
当执行方式是submit时,堆栈异常没有输出。但是调用Future.get()方法时,可以捕获到异常,不会把这个线程移除掉,也不会创建新的线程放入到线程池中。
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